I'm trying to define a block of memory that contains 5 pairs of VFO scan limits (low-high ranges). The storage is the same for the regular 750 channel memories, even though the freq field is the only significant one for the VFO scan limits..

struct channel {
  bbcd freq[4];
  bbcd offset[4];
  u8 unknownA:4,
     tune_step:4;
  ...
  u8 unknown24:4,     scramble:4;
  char name[7];
  ul16 custtone;
};

...

#seekto 0x2000;
struct channel memory[750];

...

#seekto 0x7DC0;
struct {
    channel low_limit;
    channel high_limit;
} vfo_scan_limits[5];

This gets me:

File "c:\proj\proj_chirp\chirp\chirp\bitwise_grammar.py", line 134, in parse
    return pypeg_parse(_language, FakeFileInput())
File "c:\proj\proj_chirp\chirp\chirp\pyPEG.py", line 388, in parse
    raise SyntaxError("syntax error in " + u(file) + ":" +
File "<string>", line None
SyntaxError: syntax error in input:116:     channel low_limit;

Is this just a bug in the grammar? Or, is my definition of five pairs too complicated for bitwise?

Should I stick to an array of 10 scalars, and do the odd/even math in my code? Easy enough, but not nearly as elegant.

#seekto 0x7DC0;
struct channel vfo_scan_limits[10];

Thanks

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