Re: [chirp_devel] def convert_freq_to_bytes(real_freq):

The answer is:

def convert_freq_to_bytes(freq): bytes = [ 0 for x in range(0,8) ] # init list with 8 times 0 real_freq = int(freq * 100000) # it has to be integer for i in range(7, -1, -1): # go from 7 to 0 bytes[i] = real_freq%10 # extract last digit real_freq /= 10 # throw away last digit return bytes

I'm not a python guru, may be this can be done better with some python magics but this function just works :)

73 de IZ3GME

On 22/01/2013 04:08, Jim Unroe wrote:

Hi group,

I'm trying to create a helper function to convert a floating point number to a group of bytes

For example I have this value: 146.52000 I think I need it change to something like 0x01,0x04,0x06,0x05,0x02,0x00,0x00,0x00

The first thing I beieve I need to do is shift the decimal point to the right 5 places. So I did this

 real_freq *= 100000.0

I believe this gets me 14652000

Now I think I need to do something like this to separate the individual digits

 digits =[int(i) for i in str(real_freq)]

I'm not positive, but I think this makes an array something like

digits[0] = 1 digits[1] = 4 digits[2] = 6 digits[3] = 5 digits[4] = 2 digits[5] = 0 digits[6] = 0 digits[7] = 0

Here is where I'm stuck. I've tried a few think but so far no luck. I've searched the other drivers to see if I could locate something similar. If there is, I missed it.

Then ultimately, I think I need to end with

 return bytes

So am I on the right track? Any advice on what I need to do next.

Thanks, Jim

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